Specific weight

Table of contents

Definition

Specific weight is defined as the ratio between weight and volume. Specific weight can also be defined as the product between density and gravitational acceleration. Specific weight, unlike density, is not absolute, it depends on the value of the gravitational acceleration (g), which varies depending on altitude and latitude.

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Formula

\[\gamma = \frac{G}{V}=\frac{m \cdot g}{V} \tag{1}\]

where:
G [N] – weight
V [m3] – volume
m [kg] – mass
g [m/s2] – gravitational acceleration

The density ρ [kg/m3] is the ratio between mass (m) and volume (V):

\[\rho = \frac{m}{V} \tag{2}\]

Replacing the expression of the density (2) in the formula of specific weight (1), we get:

\[\gamma = \rho \cdot g \tag{3}\]

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Unit of measurement

The symbol used for specific weight is the Greek letter γ (gamma). The SI unit of measurement for specific weight is [N/m3].

The unit of measurement for specific weight can easily be demonstrated from equation (3). The unit of measurement for density is [kg/m3]. The unit of measurement for gravitational acceleration is [m/s2]. Multiplying them as per equation (3) gives:

\[\frac{kg}{m^{3}} \cdot \frac{m}{s^{2}} = \frac{kg \cdot m}{m^{3} \cdot s^{2}} \tag{4}\]

We know that 1 N (Newton) is defined as:

\[N = \frac{kg \cdot m}{s^{2}} \tag{5}\]

Replacing (5) in (4) gives the unit of measurement for specific weight as [N/m3].

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Example on how to calculate specific weight

Example 1. The density of water at 10 °C is 999.75 kg/m3. Knowing that gravitational acceleration is 9.81 m/s2, calculate the specific weight of water at 10 °C.

Applying the formula of specific weight (3), we get:

\[\gamma = \rho \cdot g = 999.75 \cdot 9.81 = 9807.5475 \left [ \frac{N}{m^{3}} \right ] \]

Example 2. The density of air at 20 °C is 1.2041 kg/m3. Knowing that gravitational acceleration is 9.81 m/s2, calculate the specific weight of air at 20 °C.

Applying the formula of specific weight (3), we get:

\[\gamma = \rho \cdot g = 1.2041 \cdot 9.81 = 11.812221 \left [ \frac{N}{m^{3}} \right ] \]

Example 3. The density of mercury at 20 °C is 13600 kg/m3. Knowing that gravitational acceleration is 9.81 m/s2, calculate the specific weight of mercury at 20 °C.

Applying the formula of specific weight (3), we get:

\[\gamma = \rho \cdot g = 13600 \cdot 9.81 = 133416 \left [ \frac{N}{m^{3}} \right ] \]

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Specific weight of water

Since water density varies with temperature, the specific weight of water will be function of temperature.

Water temperature [°F] Water temperature [°C] Water density [kg/m3] Specific weight of water [N/m3]
32 0 999.87 9808.7247
39.2 4 1000 9810
40 4.4 999.99 9809.9019
50 10 999.75 9807.5475
60 15.6 999.07 9800.8767
70 21 998.02 9790.5762
80 26.7 996.69 9777.5289
90 32.2 995.10 9761.931
100 37.8 993.18 9743.0958
120 48.9 988.70 9699.147
140 60 983.38 9646.9578
160 71.1 977.29 9587.2149
180 82.2 970.56 9521.1936
200 93.3 963.33 9450.2673
212 100 958.65 9404.3565

Source: U.S. Department of the Interior, Bureau of Reclamation, 1977, Ground Water Manual, from The Water Encyclopedia, Third Edition, Hydrologic Data and Internet Resources, Edited by Pedro Fierro, Jr. and Evan K. Nyler, 2007.

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Specific weight of air

Since air density varies with temperature, the specific weight of air will be function of temperature.

Air temperature [°C] Air density [kg/m3] Specific weight of air [N/m3]
-25 1.4224 13.953744
-20 1.3943 13.678083
-15 1.3673 13.413213
-10 1.3413 13.158153
-5 1.3163 12.912903
0 1.2922 12.676482
5 1.2690 12.44889
10 1.2466 12.229146
15 1.2250 12.01725
20 1.2041 11.812221
25 1.1839 11.614059
30 1.1644 11.422764
35 1.1455 11.237355

Source: Wikipedia.

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Specific weight calculator

Density, ρ [kg/m3] Gravitational acceleration, g [m/s2]
Specific weight
γ [N/m3] =

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